Asked by Alex
A grocer wants to mix nuts costing $5 per kg with nuts costing $8 per kg to make a 10 kg mixture selling for $6 per kg. How much of each type should be mixed?
How do I set up this problem? Thank you.
How do I set up this problem? Thank you.
Answers
Answered by
bobpursley
let E be weight of expensive nuts, C be cheaper nuts
E*8+C*5=10*6 value equation
E+C=10 mass equation
Solve it by any method, I will do determinants
Det: 8-5=3
E= (60-50)/3=10/3 =3.33 lb
C= 80-60 /3=20/3 =6.66 lb
E*8+C*5=10*6 value equation
E+C=10 mass equation
Solve it by any method, I will do determinants
Det: 8-5=3
E= (60-50)/3=10/3 =3.33 lb
C= 80-60 /3=20/3 =6.66 lb
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.