Asked by Annie
How much faster does nitrogen monoxide (NO) effuse in comparison to dinitrogen tetraoxide (N2O4)
Answers
Answered by
DrBob222
rate NO
rate N2O4
mm NO = molar mass NO
mmN2O4 = molar mass N2O4.
(rateNO/rate N2O4) - sqrt (mmN2O4/mmNO)_
rate N2O4
mm NO = molar mass NO
mmN2O4 = molar mass N2O4.
(rateNO/rate N2O4) - sqrt (mmN2O4/mmNO)_
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