Question

if you have how do u do 2^2x - 2^x - 6 =0 (calc)how do u do it? using logs??

Answer 1

REMEMBER LOG BASE A X = Y!!!!!

THAT IS THE RULE, NOW FIND THE LOG WITH WHAT I GAVE U

IF U CANT FIND IT OUT TOO BAD, I AM NOT DOING UR HOMEWORK, BUT I CAN HELP U!!!

Answer 2

let 2^x = u , then your equation becomes
u^2 - u - 6 = 0
(u-3)(u+2) = 0
u=3 or u=-2
then 2^x = 3
x = log3/log2 = 1.58496

or 2^x = -2 which is not defined.

so x = 1.58496