Question
A man stands on the edge of a cliff with hands outstretched horizontally
carrying two stones, one in each hand. At time
t= 0, he drops the first pebble from rest. After a time of 1.0 s, he releases the second pebble. At what time will the separation between the pebbles be 66 m?
carrying two stones, one in each hand. At time
t= 0, he drops the first pebble from rest. After a time of 1.0 s, he releases the second pebble. At what time will the separation between the pebbles be 66 m?
Answers
bobpursley
66=h1-h2=1/2 gt^2-1/2 g(t-1)^2
solve for time t.
solve for time t.