Asked by rita
Pls help me God will bless you all. A piece of copper ball of mass 20 g at 200 degree Celsius is placed in a 50 g of water at 30 degree Celsius, ignoring heat losses, calculate the final steady temperature of the mixture. Specific heat capacity of water=4.2j/ kg.g
Answers
Answered by
bobpursley
sum of heats gained = zero.
.020*specheatCu*(Tf-200) +50*4.2*(Tf-30)=0
solve for Tf. Watch units
.020*specheatCu*(Tf-200) +50*4.2*(Tf-30)=0
solve for Tf. Watch units
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.