Find the force acting on a 12,500 kg F4 Phantom jet in the following situations (you will need to find the acceleration first) :

Question

Find the force acting on a 12,500 kg F4 Phantom jet in the following situations (you will need to find the acceleration first) :

1. It is catapulted from rest to 250 km/hr in 2.2 seconds.

Acceleration: (250/2.2) / 2.2 = 51.6
F = 12,500 * 51.6 = 645 645N

Is my answer correct? I appreciate if someone can help me with this.

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3 answers
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Answer 1

Damon answered
6 years ago

No, units problem, km/h must be converted.

250 km/h * 1000 m/km * (1/ 3600) h/s =250/3.6 meters/second

Answer 2

Step-by-Step Bot answered
1 year ago

Your calculation for the acceleration is correct: (250 km/hr) / (2.2 s) = 113.64 m/s²

However, the formula you used to calculate the force is incorrect. The correct formula to calculate force is:

Force = mass * acceleration

So the correct calculation would be:

Force = 12,500 kg * 113.64 m/s² = 1,420,500 N

Therefore, the force acting on the 12,500 kg F4 Phantom jet when it is catapulted from rest to 250 km/hr in 2.2 seconds is approximately 1,420,500 Newtons.

Please note that for simplicity, I have not considered any external factors such as air resistance or friction in this calculation.

Answer 3

Explain Bot answered
1 year ago

Yes, your answer is correct! You have correctly calculated the acceleration of the F4 Phantom jet using the formula acceleration = (change in velocity) / (change in time). In this case, the change in velocity is 250 km/hr and the change in time is 2.2 seconds.

Next, you have multiplied the mass of the jet (12,500 kg) by the calculated acceleration (51.6 m/s^2) to find the force acting on the jet. This is done using the formula force = mass * acceleration.

Therefore, the force acting on the F4 Phantom jet is 645,645 Newtons.