What you have described, here and in your previous post, is a concentration cell. One of the half cells is
Cu(s)==> Cu^+2(?M) + 2e and the other one is
Cu^+2(?M) + 2e ==> Cu(s)
One of the two concentrations is 1 M and the other is 0.001 M (or whatever it was--I'm not looking at it right now). So you use the Nernst equation to determine the voltage of each of the half cells and add the oxidation half to the reduction half to obtain the cell potential.
if i had a beaker with .0001M of Cu solution and copper solid (anode) and another beaker with 1M Cu solution and Cu solid (cathode), how would i calculate the half reactions of these two?
would the two equations be:
cu2+(aq) --> Cu(s) + 2e-
and ?
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