Asked by Diya
                The towns of Franklin and Chester each decided in the same year to begin posting their populations on signs by the main entrances into the towns. Each year, they update the signs.
Franklin had a population of 20,000 people in the first year that they posted the sign, and each year, the population increases by approximately 5%
Chester had a population of 25,000 people in the first year that they posted the sign, and each year, the population increases by 500 people.
In which year will Franklin's population first exceed Chester's population?
            
        Franklin had a population of 20,000 people in the first year that they posted the sign, and each year, the population increases by approximately 5%
Chester had a population of 25,000 people in the first year that they posted the sign, and each year, the population increases by 500 people.
In which year will Franklin's population first exceed Chester's population?
Answers
                    Answered by
            Steve
            
    you want the geometric progression and the arithmetic progression to be equal after n years. That is,
20000*1.05^(n-1) = 25000+500(n-1)
n = 8.4
so, 8.4 years after they started posting populations, the signs will read the same.
Thus, after 9 years Franklin's population will be greater.
    
20000*1.05^(n-1) = 25000+500(n-1)
n = 8.4
so, 8.4 years after they started posting populations, the signs will read the same.
Thus, after 9 years Franklin's population will be greater.
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