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A car travels along a straight road for 30 seconds starting at time t = 0. Its acceleration in ft/sec2 is given by the linear g...Asked by Anonymous
A car travels along a straight road for 30 seconds starting at time t = 0. Its acceleration in ft/sec2 is given by the linear graph below for the time interval [0, 30]. At t = 0, the velocity of the car is 0 and its position is 10.
What is the velocity of the car when t = 6?
I can't show the graph, but the y intercept is at (0,10) and the x intercept is (10,0).
So if the equation of the graph is 10-t, then the velocity equation would be 10t-t^2/2+C and I got C to be 0. I got 42 ft/sec to be my answer for the velocity at t=6 by plugging 6 in for t. Is this all there is to it or is there something I'm missing regarding the position formula?
What is the velocity of the car when t = 6?
I can't show the graph, but the y intercept is at (0,10) and the x intercept is (10,0).
So if the equation of the graph is 10-t, then the velocity equation would be 10t-t^2/2+C and I got C to be 0. I got 42 ft/sec to be my answer for the velocity at t=6 by plugging 6 in for t. Is this all there is to it or is there something I'm missing regarding the position formula?
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