Two chords AB and CD of A circle intersect at right angle at a point inside the circle if m(angle BAC is 35 degree find m(angle ABD)

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To find the measure of angle ABD, we can use the properties of intersecting chords.

Step 1: Draw a diagram of the given situation. Label the points as described.
- Circle with center O
- Chords AB and CD intersecting at point E at a right angle.
- Angle BAC measures 35 degrees.

Step 2: Identify any relevant theorems or properties.
- The theorem we will use is that if two chords intersect in a circle, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.
- In this case, we have AE * EB = CE * ED.

Step 3: Use the theorem to set up an equation that will allow us to solve for the unknown angle.
- Let AE = a and CE = b.
- Since AE * EB = CE * ED, we can substitute these values into the equation.

a * (a + EB) = b * (b + ED)

Step 4: Simplify the equation.
- Expand the equation by multiplying the terms.

a^2 + a * EB = b^2 + b * ED

Step 5: Use the information given to substitute known values into the equation.
- We know that angle BAC measures 35 degrees, and angle ABE is a right angle (90 degrees).
- This means angle AEB is 180 - 35 - 90 = 55 degrees.

- Substituting EB = a * sin(AEB) and ED = b * sin(AEC) into the equation, we get:

a^2 + a * a * sin(AEB) = b^2 + b * b * sin(AEC)

Step 6: Simplify the equation further using trigonometric identities.
- We can use the identities sin(AEB) = sin(90) = 1 and sin(AEC) = sin(AEB + 35) = sin(55 + 35) = sin(90) = 1.

a^2 + a^2 * 1 = b^2 + b^2 * 1

Step 7: Combine like terms and solve for the unknown quantities.
- Simplify the equation.

2a^2 = 2b^2

- Divide both sides by 2.

a^2 = b^2

- Take the square root of both sides.

a = b

Step 8: Determine the measure of angle ABD.
- Since AE = CE and angle AEB is a right angle, angle ABD and angle BCD will be congruent.
- Therefore, angle ABD measures 35 degrees.

In conclusion, the measure of angle ABD is 35 degrees.