Asked by Sophia
An airplane traveling 1001 m above the ocean at 125km/h is going to drop a box of supplies to shipwrecked victims below. What is the horizontal distance between the plane and the victims when the box is dropped?
Answers
Answered by
Sophia
The time is 14.3s, btw..
Answered by
drwls
The time T that it will take the box to fall 1001 m, neglectring air resistance, is given by the equation
(g/2)T^2 = 1001
T^2 = 2002/9.8 = 204.3 s^2
T = 14.3 s
The distance that the box moves forward while it falls is V*T.
You will need to convert the 125 km/h speed to ___ m/s to get the distance in meters.
(g/2)T^2 = 1001
T^2 = 2002/9.8 = 204.3 s^2
T = 14.3 s
The distance that the box moves forward while it falls is V*T.
You will need to convert the 125 km/h speed to ___ m/s to get the distance in meters.
Answered by
Alison
Givens:
a=-9.81m/s^2
d=-1001m
vi=0m/s
d=vit+1/2at^2
-1001m=1/2-9.81m/s^2t^2
-1001m=-4.905m/s^2t^2
divide -1001m by -4.905m/s^2
204s^2=t^2
square root both sides
14.3s=t
125km/hr is 56m/s
56*14.3=
800.8m, that's the distance from the package dropped.
a=-9.81m/s^2
d=-1001m
vi=0m/s
d=vit+1/2at^2
-1001m=1/2-9.81m/s^2t^2
-1001m=-4.905m/s^2t^2
divide -1001m by -4.905m/s^2
204s^2=t^2
square root both sides
14.3s=t
125km/hr is 56m/s
56*14.3=
800.8m, that's the distance from the package dropped.
Answered by
Alison
Woops!
125km/hr is 34.7m/s
so 34.7*14.3 is 496.21m
125km/hr is 34.7m/s
so 34.7*14.3 is 496.21m
Answered by
Michael
7.8m/s
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