Asked by Sophia

An airplane traveling 1001 m above the ocean at 125km/h is going to drop a box of supplies to shipwrecked victims below. What is the horizontal distance between the plane and the victims when the box is dropped?

Answers

Answered by Sophia
The time is 14.3s, btw..
Answered by drwls
The time T that it will take the box to fall 1001 m, neglectring air resistance, is given by the equation
(g/2)T^2 = 1001
T^2 = 2002/9.8 = 204.3 s^2
T = 14.3 s
The distance that the box moves forward while it falls is V*T.

You will need to convert the 125 km/h speed to ___ m/s to get the distance in meters.
Answered by Alison
Givens:
a=-9.81m/s^2
d=-1001m
vi=0m/s

d=vit+1/2at^2

-1001m=1/2-9.81m/s^2t^2
-1001m=-4.905m/s^2t^2
divide -1001m by -4.905m/s^2

204s^2=t^2
square root both sides

14.3s=t

125km/hr is 56m/s
56*14.3=
800.8m, that's the distance from the package dropped.
Answered by Alison
Woops!
125km/hr is 34.7m/s
so 34.7*14.3 is 496.21m
Answered by Michael
7.8m/s
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions