Asked by caphas

A force of 300N is sufficient to keep a 100_kg wooden crate moving at constant velocity across a wooden floor. what is the coefficient of kinetic friction?

Answers

Answered by Damon
300 = mu m g = mu * 100 * 9.81
That is it. Try yourself now.
Answered by Henry
M*g = 100 * 9.8 = 980 N. = Wt. of crate = Normal (Fn),
Fk = u*Fn = u * 100 = 100u = Force of kinetic friction,
F - Fk = M*a,
300 - 100u = 100*0 = 0,,
u = 3.

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