Make r the subject of formula t=2πr(r+h)

Answer 1

so you will be re-arranging to get r all by itself...
it is a wee bit tricky due to the r inside and outside of the bracket.
Do you usually treat it like a quadratic and factor it?
Because that would be a lovely solution : )

Answer 2

t=2πr(r+h)
t = 2πr^2 + 2πhr
2πr^2 + 2πhr - t = 0
this is a quadratic in r, where a = 2π , b = 2πh and c = -t

r = (-2πh ± √(4π^2h^2 - 4(2π)(-t) )/(4π)

see if you can simplify that

Answer 3

explain in detail

Answer 4

I don't understand

Answer 5

I don understand

Answer 6

I don’t understand

Answer 7

I don't understand anything 🤪 about this

Answer 8

I don't understand

Answer 9

Not even a single number I can understand

Answer 10

r=A-h