Asked by Victor
Make r the subject of formula t=2πr(r+h)
Answers
Answered by
MsPi_3.14159265
so you will be re-arranging to get r all by itself...
it is a wee bit tricky due to the r inside and outside of the bracket.
Do you usually treat it like a quadratic and factor it?
Because that would be a lovely solution : )
it is a wee bit tricky due to the r inside and outside of the bracket.
Do you usually treat it like a quadratic and factor it?
Because that would be a lovely solution : )
Answered by
Reiny
t=2πr(r+h)
t = 2πr^2 + 2πhr
2πr^2 + 2πhr - t = 0
this is a quadratic in r, where a = 2π , b = 2πh and c = -t
r = (-2πh ± √(4π^2h^2 - 4(2π)(-t) )/(4π)
see if you can simplify that
t = 2πr^2 + 2πhr
2πr^2 + 2πhr - t = 0
this is a quadratic in r, where a = 2π , b = 2πh and c = -t
r = (-2πh ± √(4π^2h^2 - 4(2π)(-t) )/(4π)
see if you can simplify that
Answered by
Emediong
explain in detail
Answered by
Emediong
I don't understand
Answered by
I don understand
I don understand
Answered by
Anonymous
I don’t understand
Answered by
Kahjah Simmonds
I don't understand anything 🤪 about this
Answered by
Kahjah Simmonds
I don't understand
Answered by
Anna
Not even a single number I can understand
Answer
r=A-h
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