Asked by George Carl
Find the value(s) of a making v =6ai−3j parallel to w =a^2i+9j .
a=
a=
Answers
Answered by
Reiny
To be parallel
a^2/6a = 9/-3 = -3
a^2 = -18a
a^2 + 18a = 0
a(a+18) = 0
a = 0 or a = -18
check:
if a = 0 your vectors are <0,-3> and <0,9) which are parallel
if a = -18 your vectors are <-108,-3> and <324,9)
since <324,9> = -3<-108,-3> they are parallel
a^2/6a = 9/-3 = -3
a^2 = -18a
a^2 + 18a = 0
a(a+18) = 0
a = 0 or a = -18
check:
if a = 0 your vectors are <0,-3> and <0,9) which are parallel
if a = -18 your vectors are <-108,-3> and <324,9)
since <324,9> = -3<-108,-3> they are parallel
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