Question

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as i earlier posted and , 1 day ago , i am confusesd hw we ll find freezing point......isnt it T pure solvent - T solution .. which ll be 0-(-23.3) = 23.3
plz conform .. and do we have to use Kf.m .. formula in order to get
( -23.3)(1)= -23.3 .. as someone earlier posted plz can u conform thnks

i am confused

What mass of ethylene glycol C2H6O2, the main component of antifreeze, must be added to 10.0 L water to produce a solution for use in a car's radiator that freezes at -23C? Assume density for water is exactly 1g/mL.

Answer 1

Note: It would be much much easier to read your question if you wrote it in ordinary English which means no text type words, end sentence with a period and start a new sentence with a capital letter.
Now for the question.
delta T = Kf*m (yes, Kf*m must be used).
You know delta T. It is 23 from the problem (0 - (-23) = 23.
Kf = 1.86. Use the formula to calculate m, molality.
Then use m = #mols/kg solvent.
You know m from the previous problem and you know kg solvent (it is 10.0L with a density of 1 g/mL), calculate mols.
Now use mols = grams/molar mass. You know mols and molar mass which allows you to calculate grams.