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On 2 November 2006, Henry saved $1200 in an account that pays 8.6% per annum simple interest. Three years later, he added anoth...Asked by melon
On 2 November 2006, Romy saved RM 1,200 in an account that pay 8.6% per annum simple interest. Three years later, he added another RM 500 into the account. Find the amount in his account on 2 November 2012.
Answers
Answered by
Henry
After 3 years:
P = Po + Po*r*t + 500,
P = 1200 + 1200*0.086*3 + 500 = $2009.60,
After 6 years:
P = 2009.60 + 2009.60*0.086*3 =
P = Po + Po*r*t + 500,
P = 1200 + 1200*0.086*3 + 500 = $2009.60,
After 6 years:
P = 2009.60 + 2009.60*0.086*3 =
Answered by
Reiny
amount = 1200 + 1200(6)(.086) + 500 + 500(3)(.086)
= .....
= .....
Answered by
Henry
post it.
Answered by
Reiny
I must disagree with Henry's answer.
He is using a combination of simple and compound interest.
The 2009.60 in his first step includes the simple interest earned.
He then includes that in the calculation of simple interest in part 2
That makes it compound interest.
He is using a combination of simple and compound interest.
The 2009.60 in his first step includes the simple interest earned.
He then includes that in the calculation of simple interest in part 2
That makes it compound interest.
Answered by
Anonymous
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Answered by
Anonymous
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Answered by
Anonymous
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Answered by
Anonymous
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Answered by
melon
Thanks!
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