A(-11,8)B(2,-6) and C(-19,-8) are the vertices of Triangle ABC. N(X,Y) is a point on AC such the BN is Perpendicular to AC. Find Area of Triangle ABC. PLEASE HELP!!!

Answer 1

The second sentence is not needed.

Draw the triangle. Compute the side lengths

s1=AB= sqrt ((bx-ax)^2+(by-ay)^2 )
= sqrt ( 13^2 + (-14)^2 )= sqrt (169+256)=20.6

and do that for all sides. Then knowing the sides, calculate the perimeter, divide by 2. Let that be p.

Area=sqrt (p(p-a)(p-b)(p-c))

Or you can do it here
http://www.analyzemath.com/Geometry_calculators/perimeter_area_tri_verti.html