Find ln(1/(√(ab^3)) of lna = 2 and lnb = 3.

Question

= ln1 - ln(ab)^(3/2)

= ln1 - lna^(3/2) + lnb^(3/2)

= 0 - 3/2(lna) + 3/2(lnb)

= -3/2(2) + 3/2(3)

= 1.5

--textbook answer is -5.5 ... where did I go wrong?

Answer 1

ln [ 1/{a^(1/2)b^(3/2)} ]
ln [a^-1/2 b^-3/2]
ln a^-1/2 + ln b^-3/2
-1/2 ln a -3/2 ln b
-1/2 (2) - 3/2 (3)