Question
Uranus is approximately 2.74 x 10^9 km away from the Sun at perihelion and 3.00 x 10^9 km at aphelion. Find the eccentricity of Uranus's orbit given that the perihelion is r = a(1 - e) and the aphelion is r = a(1 + e).
Answers
Steve
so, plug and chug.
a/(1-e) = 3.00*10^9
a/(1+e) = 2.74*10^9
a = 2.86*10^9
e = 0.0453
a/(1-e) = 3.00*10^9
a/(1+e) = 2.74*10^9
a = 2.86*10^9
e = 0.0453
ridge lee
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