Question
Locate the center of mass of three particles of mass m1=1.0kg,m2= 2.0kg, and m3= 3.0kg at the corners of an equilateral triangle 1.0m on a side
Answers
bobpursley
lt (0,0) be one corner where m1 is, and the x axis along the line from m1 to m3.
cg*totalmass=(0,0)*1 + (1,0)*2 + (.5,.707)3
cg=i(0+2+1.5)/6+j(0+O+2.12)/6
cg= i(3.5/6) + j(2.12/6) where i is in base direction,j is perpendicular to it,measured from one base corner
cg*totalmass=(0,0)*1 + (1,0)*2 + (.5,.707)3
cg=i(0+2+1.5)/6+j(0+O+2.12)/6
cg= i(3.5/6) + j(2.12/6) where i is in base direction,j is perpendicular to it,measured from one base corner