Asked by John
If sin a=0.31 cos a=0.95 sin b=0.47 and cos b=0.88 what is sin (a+b)?
0.78
-0.17
0.98
0.72
0.78
-0.17
0.98
0.72
Answers
Answered by
bobpursley
sin(a+b)=sinacosb+sinbcosa=.31*.88+.47*.95= I get about .72
Answered by
anke
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