Asked by Ashlyn
The base of a rectangle is on the x-axis and its two upper vertices are on the parabola y=25-x^2. of all such rectangles, what are the dimensions of the one with greatest area?
Answers
Answered by
Steve
Clearly the maximum area is when the rectangle is centered on the parabola's axis of symmetry. In this case, x=0. So, let the base of the rectangle be of length 2x. Its area is thus
A = 2xy = 2x(25-x^2) = 50x-2x^3
dA/dx = 50-6x^2
dA/dx=0 when x=5/√3
So, the maximum area is (10/√3)(25-(5/√3)^2) = 500/(3√3)
A = 2xy = 2x(25-x^2) = 50x-2x^3
dA/dx = 50-6x^2
dA/dx=0 when x=5/√3
So, the maximum area is (10/√3)(25-(5/√3)^2) = 500/(3√3)
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