Asked by Cadie
rewrite the given equation using the substitutions x=r cos theta and y=r sin theta. Simplify your answer. x^2+y^2+3x=0
Answers
Answered by
Steve
so, what's the trouble? Just plug and chug.
x^2+y^2 = r^2, so
r^2+3rcosθ = 0
r(r+3cosθ) = 0
If you want just r=f(θ) then you have to solve for r using the quadratic formula.
x^2+y^2 = r^2, so
r^2+3rcosθ = 0
r(r+3cosθ) = 0
If you want just r=f(θ) then you have to solve for r using the quadratic formula.
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