Asked by huncho jack
Name the axis to which the major axis is parallel and find the center of
25(x+5)^(2)+4(y-3)^(2)=100
I think that the center is (-5,3). Is that correct?
I need help with finding out which axis the major axis is parallel to. I do not know how to do it.
25(x+5)^(2)+4(y-3)^(2)=100
I think that the center is (-5,3). Is that correct?
I need help with finding out which axis the major axis is parallel to. I do not know how to do it.
Answers
Answered by
Damon
center is correct
25(x+5)^(2)+4(y-3)^(2)=100
(x+5)^2 / 4 + (y-3)^2 / 25 = 1
(x+5)^2 / 2^2 + (y-3)^2 / 5^2 = 1
which is bigger , 5 or 2 ?
25(x+5)^(2)+4(y-3)^(2)=100
(x+5)^2 / 4 + (y-3)^2 / 25 = 1
(x+5)^2 / 2^2 + (y-3)^2 / 5^2 = 1
which is bigger , 5 or 2 ?
Answered by
Damon
to make that easier look at
x^2/2^2 + y^2/5^2
x^2/2^2 + y^2/5^2
Answered by
huncho jack
5^2 is bigger.
Answered by
Damon
You got it.
now what is x when y = 0 and what is y when x = 0 in
x^2/2^2 + y^2/5^2 = 1
???????????????????????
now what is x when y = 0 and what is y when x = 0 in
x^2/2^2 + y^2/5^2 = 1
???????????????????????
Answered by
Damon
all I did was move the center to the origin.
Answered by
huncho jack
x=2 and y=5
Answered by
Damon
x = + or - 2 along x axis
y = + or - 5 along y axis
now which is longer ? :)
y = + or - 5 along y axis
now which is longer ? :)
Answered by
Damon
Draw x and y axis system and mark those points, then draw an ellipse through them !
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