Asked by Anonymous
terry takes a bus journey of 9km travelling at an average speed of 36km/h a) calculate the time taken in minutes for the bus journey. He then walks the remaining 2km to his home in 20 minutes. b) calculate his average walking speed in km/h. c) calculate terry's average speed for the entire journey from school to his home.
Answers
Answered by
Steve
distance = speed * time
(a) (9km)/(36km/hr) = (9/36)hr
(b) 20 min = 1/3 hr, so (2km)/(1/3 hr) = 6km/hr
average speed is total distance divided by total time
(c) (9+2)km/(1/4 + 1/3)hr = 11/(7/12) = 132/7 km/hr
I leave it to you to simplify the final values.
(a) (9km)/(36km/hr) = (9/36)hr
(b) 20 min = 1/3 hr, so (2km)/(1/3 hr) = 6km/hr
average speed is total distance divided by total time
(c) (9+2)km/(1/4 + 1/3)hr = 11/(7/12) = 132/7 km/hr
I leave it to you to simplify the final values.
Answered by
Henry
a. T = 9km/36km/h = 0.25h = 15 min.
b. r = 2km/20min = 0.10 km/min = 6 km/h.
c. r = d/T = 11km/(15+20)min. =
b. r = 2km/20min = 0.10 km/min = 6 km/h.
c. r = d/T = 11km/(15+20)min. =
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