Asked by Alexander
Don is 21 years older than Betty. In six year Don will be twice as old as Betty. How old is each now?
Answers
Answered by
Steve
If b is betty's age, then Don is b+21
In 5 years their ages will be b+6 and b+27
So,
b+27 = 2(b+6)
Solve for b, then you can get Don's age.
In 5 years their ages will be b+6 and b+27
So,
b+27 = 2(b+6)
Solve for b, then you can get Don's age.
Answered by
Henry
Betty is X years old.
Don is X+21 years old.
Six years from now:
Betty: X+6 years old.
Don: (X+21) + 6.
(X+21)+6 = 2(x+6).
X = ?
x+21 = ?
don
; (
Don is X+21 years old.
Six years from now:
Betty: X+6 years old.
Don: (X+21) + 6.
(X+21)+6 = 2(x+6).
X = ?
x+21 = ?
don
; (