Question

c^2 - 8c + 16 - y^2

(c + 4) (c + 4)

(c + 4)^2 - y^2

(c +4 +y) (c + 4 - y)

Is this correct?

Answer 1

Is the problem
c^2 - 8c + 16 - y^2 = 0?

Answer 2

no

it is

c^2 -8c + 16 - y^2

and it says to factor completely

Answer 3

Sorry, I am not sure what they are asking. Someone else here might understand it.

Answer 4

c^2 - 8c + 16 - y^2 = (c-4)^2 - y^2
= (c-4+y)(c-4-y)

Answer 5

Thanks Guys.