Asked by Jennifer

c^2 - 8c + 16 - y^2

(c + 4) (c + 4)

(c + 4)^2 - y^2

(c +4 +y) (c + 4 - y)

Is this correct?
Answered by Quidditch
Is the problem
c^2 - 8c + 16 - y^2 = 0?
Answered by Jennifer
no

it is

c^2 -8c + 16 - y^2

and it says to factor completely
Answered by Quidditch
Sorry, I am not sure what they are asking. Someone else here might understand it.
Answered by drwls


c^2 - 8c + 16 - y^2 = (c-4)^2 - y^2
= (c-4+y)(c-4-y)

Answered by Jennifer
Thanks Guys.
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