Is the problem
c^2 - 8c + 16 - y^2 = 0?
c^2 - 8c + 16 - y^2
(c + 4) (c + 4)
(c + 4)^2 - y^2
(c +4 +y) (c + 4 - y)
Is this correct?
5 answers
no
it is
c^2 -8c + 16 - y^2
and it says to factor completely
it is
c^2 -8c + 16 - y^2
and it says to factor completely
Sorry, I am not sure what they are asking. Someone else here might understand it.
c^2 - 8c + 16 - y^2 = (c-4)^2 - y^2
= (c-4+y)(c-4-y)
= (c-4+y)(c-4-y)
Thanks Guys.