Asked by Nikki
Ok, I have two questions first:
1. I'm asked to find a cartesian equation for the polar graph of this polar equation: r^2 = sin(2(theta))
The answer I got was
(x^2+y^2)^2/(2xy) = 2
Is this the correct way to express it?
2. I need to find the cartesian equation for this parametric equation:
x = sec(t) + tan(t)
y = sec(t) - tan(t)
I have tried using the identity tan^2x + 1 = sec^2x, but I feel like I'm moving in circles!
I'd appreciate it so much if someone could help me!!! Thanks =)
2. x + y = 2 sec t
x - y = 2 tan t
(1/4)(x+y)^2 = (1/4)(x-y)^2 + 1
This gets rid of the t terms. Rearrange and simplify.
1. I'm asked to find a cartesian equation for the polar graph of this polar equation: r^2 = sin(2(theta))
The answer I got was
(x^2+y^2)^2/(2xy) = 2
Is this the correct way to express it?
2. I need to find the cartesian equation for this parametric equation:
x = sec(t) + tan(t)
y = sec(t) - tan(t)
I have tried using the identity tan^2x + 1 = sec^2x, but I feel like I'm moving in circles!
I'd appreciate it so much if someone could help me!!! Thanks =)
2. x + y = 2 sec t
x - y = 2 tan t
(1/4)(x+y)^2 = (1/4)(x-y)^2 + 1
This gets rid of the t terms. Rearrange and simplify.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.