Asked by ashari
A rectangular box is 6 in. wide, 6 in. tall, and 12 in. long. What is the diameter of the smallest circular opening through which the box will fit?
Answers
Answered by
Damon
hypotenuse diagonal of square
6^2 + 6^2 = d^2
d = 6 sqrt 2
6^2 + 6^2 = d^2
d = 6 sqrt 2
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