Asked by Huseen

A 10 cm long, 2cm wide wooden wedge is pushed into a soft wood block.calculate: a) the velocity ratio of the wedge b) the load on the soft wood if the effort applied is 30N
Answered by Damon
Tricky
If it goes in 10 cm, the wood on the left is pushed 1 cm and the wood on the right is pushed 1 cm.
Therefore I would say the velocity of the wood on each side of the wedge was 1/10 times the velocity of the wedge.
30 * 10 = 300 Newtons
Answered by Abi
800
Answered by zemedku
thanks
Answered by biruk asefa
The velocity ratio of the eedge
Answered by Yididya teshome
VR=L×T
10cm=0.1m
2cm=0.02
0.02×0.1
0.002
Answered by Amanuel
Physics unit 5 review questions pag 138&139