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A rifle with a mass of 0.9 fires a bullet with a mass of 6.0 g (0.006 kg). The bullet moves with a muzzle velocity of 750 m/s after the rifle is fired.

A. What is the momentum of the bullet after the rifle is fired?
B. If external forces acting on the rifle can be ignored, what if the recoil velocity of the rifle?

1 answer

m v = .006 * 750

0.9 u + .006 * 750 = 0 since there was zero momentum before you pulled the trigger.
u = -.006*750/0.9
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