Asked by Chris
In Pittsburgh, children bring their old jack-o-lanterns to the top of the Carnegie Science Center for the annual Pumpkin Smash and compete for accuracy in hitting a target on the ground. Suppose that the building is 23m high and that the bulls-eye is a horizontal distance of 4.5m from the launch point. If the pumpkin is thrown horizontally, what is the launch speed needed to hit the bulls-eye?
Answers
Answered by
Steve
how long does it take to fall 23m?
4.9t^2 = 23
speed = distance/time
4.9t^2 = 23
speed = distance/time
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