Asked by connexus
4. what is the value of 2x^-2y^-2 for x=3 and y=-2?
1/18
72
2(-6)^-4
1/648
5.what is the value of 1/2-2x-3y5 for x=2 and 7=-4
16
-4
-1/32
-16
1/18
72
2(-6)^-4
1/648
5.what is the value of 1/2-2x-3y5 for x=2 and 7=-4
16
-4
-1/32
-16
Answers
Answered by
Steve
huh. Just plug in the numbers. I'll do the first one...
2x^-2y^-2 for x=3 and y=-2
= 2 * 3^-2 * (-2)^-2
= 2 * 1/3^2 * 1/(-2)^2
= 2 * 1/9 * 1/4
= 1/18
These aren't as hard as they look, as long as you are careful with each step.
so, what do you get for the other one?
2x^-2y^-2 for x=3 and y=-2
= 2 * 3^-2 * (-2)^-2
= 2 * 1/3^2 * 1/(-2)^2
= 2 * 1/9 * 1/4
= 1/18
These aren't as hard as they look, as long as you are careful with each step.
so, what do you get for the other one?
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