Asked by joy
A wheel starts from rest and in 10.65 s is rotating with an angular speed of 5.810 π rad/s.
(a) Find the magnitude of the constant angular acceleration of the wheel. rad/s^2
(b) Through what angle does the wheel move in 6.085 s? rad
(a) Find the magnitude of the constant angular acceleration of the wheel. rad/s^2
(b) Through what angle does the wheel move in 6.085 s? rad
Answers
Answered by
Steve
(a) clearly the acceleration is
(5.810π rad/s)/(10.65s) = 1.714 rad/s^2
(b) starting from when? t=0, or after reaching the final speed?
just as with linear motion, the "distance" (total radians) is 1/2 at^2
(5.810π rad/s)/(10.65s) = 1.714 rad/s^2
(b) starting from when? t=0, or after reaching the final speed?
just as with linear motion, the "distance" (total radians) is 1/2 at^2
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