Asked by some kid
Find the antiderivatives.
1) çãx (x+1) dx
2) ç(x^3-4)/ (x^2) dx
3) ç(3sinx) dx
4) ç(5secxtanx) dx
5) ç(1/x) dx
6) ç(e^x - 2x) dx
7) ç(3)/((1-x^2)^1/2) dx
I picked the antiderivatives i did not know how to do. Please show me how to do a couple of these.
1) çãx (x+1) dx
2) ç(x^3-4)/ (x^2) dx
3) ç(3sinx) dx
4) ç(5secxtanx) dx
5) ç(1/x) dx
6) ç(e^x - 2x) dx
7) ç(3)/((1-x^2)^1/2) dx
I picked the antiderivatives i did not know how to do. Please show me how to do a couple of these.
Answers
Answered by
some kid
the weird symbols in front are supposed be integral signs but watever. i got number 1 and i have the rest i need someone to check the rest.
2)(1/2x^2)/(-4x)
3)-cosx
4)5secx + c
5)0
6)e^x - x^2
7) 3sinx
2)(1/2x^2)/(-4x)
3)-cosx
4)5secx + c
5)0
6)e^x - x^2
7) 3sinx
Answered by
Reiny
#2, I would change
(x^3-4)/ (x^2) to x - 4x^-2
and the integral of that is
(1/2)x^2 + 4x^-1 + c
check by differentiating my answer, it is right.
#3, you had
-cosx, how could you get the 3sinx from that?
should have been -3cosx + c
#4
if y = secx
isn't y' = secxtanx ??
take care of the 5, and you are done
#5, you should recognize some standard functions and their derivatives,
if y = lnx
isn't y' = 1/x ??? , so .....
#6, good
#7, how can the derivative of 3sinx, your answer, possibly be (3)/((1-x^2)^1/2) ?????
(x^3-4)/ (x^2) to x - 4x^-2
and the integral of that is
(1/2)x^2 + 4x^-1 + c
check by differentiating my answer, it is right.
#3, you had
-cosx, how could you get the 3sinx from that?
should have been -3cosx + c
#4
if y = secx
isn't y' = secxtanx ??
take care of the 5, and you are done
#5, you should recognize some standard functions and their derivatives,
if y = lnx
isn't y' = 1/x ??? , so .....
#6, good
#7, how can the derivative of 3sinx, your answer, possibly be (3)/((1-x^2)^1/2) ?????
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.