Asked by T
A rectangular flower bed is to be created so that the length is 3 m more than the width. If the length of the diagonal of the flower bed is 15 m, determine the length and the width.
Answers
Answered by
Damon
y = x + 3
y^2 + x^2 = 15^2 = 225
(x+3)^2 + x^2 = 225
x^2 + 6 x + 9 + x^2 = 225
2 x^2 + 6 x - 216 = 0
x^2 + 3 x - 108 = 0
https://www.mathsisfun.com/quadratic-equation-solver.html
y^2 + x^2 = 15^2 = 225
(x+3)^2 + x^2 = 225
x^2 + 6 x + 9 + x^2 = 225
2 x^2 + 6 x - 216 = 0
x^2 + 3 x - 108 = 0
https://www.mathsisfun.com/quadratic-equation-solver.html
Answered by
Reiny
width--- x
length ---- x+3
x^ + (x+3)^2 = 15^2
solve for x, reject the negative answer for x
length ---- x+3
x^ + (x+3)^2 = 15^2
solve for x, reject the negative answer for x
Answered by
dsf
yes
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