Asked by gagan

A farmer has $2400 to spend to fence two rectangular pastures.The local contractor will build the fence at a cost of $6.25/m. What is the largest area that the farmer can have fenced for that price?
Answered by Writeacher
To quote one of our very good math and science tutors: “You will find here at Jiskha that long series of questions, posted with no evidence of effort or thought by the person posting, will not be answered. We will gladly respond to your future questions in which <b>your thoughts</b> are included.”
Answered by Steve
The farmer can buy $2400 / $6.25/m = 384m of fence. 384m/2 = 192m for each of the 2 rectangular pastures. A square is the rectangle with the largest area for a given perimeter, so each square will have sides of 192m/4 = 48m. Each pasture will thus have area of 48m x 48m = 2304 sq.m, and so the total area for both pastures will be 2304 x 2 = 4608 sq. m.
There are no AI answers yet. The ability to request AI answers is coming soon!