Asked by Naran
If 15.00 g of solid zinc reacts with 100.0 mL of 4.00 M hydrochloric acid, what volume of hydrogen gas is produced at 25°C and 1.00 atm?
Answers
Answered by
Steve
15g Zn = 0.229 moles
100mL of 4M HCl = 0.4 moles
Zn + 2HCl -> ZnCl2 + H2
The 0.4 moles of HCl are used up first, producing 0.2 moles of H2
Now recall that 1 mole of H2 at STP occupies 22.4L and finish up using PV=kT
100mL of 4M HCl = 0.4 moles
Zn + 2HCl -> ZnCl2 + H2
The 0.4 moles of HCl are used up first, producing 0.2 moles of H2
Now recall that 1 mole of H2 at STP occupies 22.4L and finish up using PV=kT
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