Asked by Zach
A 12801 kg freight train, coasting at 19 m/s, strikes a stationary 2445 kg box car. Determine the "CHANGE IN MOMENTUM" for the freight train if the freight train and the box car couple together. Hint: Draw an "IF Chart" to solve.
i got -39005.01
i got -39005.01
Answers
Answered by
Henry
Given:
M1 = 12,801kg, V1 = 19 m/s.
M2 = 2445kg, V2 = 0.
V3 = Velocity of M1 and M2 after collision.
Momentum before = Momentum after:
M1*V1 + M2*V2 = M1*V3 + M2*V3.
12,801*19 + 2445*0 = 12,801V3 + 2445V3,
V3 = 15.953 m/s.
M1*V1 = 12,801 * 19 = 243,219 = Momentum before collision.
M1*V3 = 12,801*15.953 = 204,214 = Momentum of M1(freight) after collision.
204,214 - 243,219 = -39,005 = Change(decrease) in momentum.
M1 = 12,801kg, V1 = 19 m/s.
M2 = 2445kg, V2 = 0.
V3 = Velocity of M1 and M2 after collision.
Momentum before = Momentum after:
M1*V1 + M2*V2 = M1*V3 + M2*V3.
12,801*19 + 2445*0 = 12,801V3 + 2445V3,
V3 = 15.953 m/s.
M1*V1 = 12,801 * 19 = 243,219 = Momentum before collision.
M1*V3 = 12,801*15.953 = 204,214 = Momentum of M1(freight) after collision.
204,214 - 243,219 = -39,005 = Change(decrease) in momentum.
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