Question
This system has one solution.
y=8x−14
y=x^2+4x−10
What is the y-coordinate of the solution?
y=8x−14
y=x^2+4x−10
What is the y-coordinate of the solution?
Answers
Arora
y = 8x - 14
y = x^2 + 4x - 10
From these equations, you get:
8x - 14 = x^2 + 4x - 10
4x - 4 = x^2
x^2 - 4x + 4 = 0
(x - 2)^2 = 0
x - 2 = 0
x = 2
So, the x-coordinate of the solution is 2.
You can simply plus this into either equation to find the y-coordinate.
y = 8x - 14
= 8(2) - 14
= 16 - 14
= 2
y = x^2 + 4x - 10
From these equations, you get:
8x - 14 = x^2 + 4x - 10
4x - 4 = x^2
x^2 - 4x + 4 = 0
(x - 2)^2 = 0
x - 2 = 0
x = 2
So, the x-coordinate of the solution is 2.
You can simply plus this into either equation to find the y-coordinate.
y = 8x - 14
= 8(2) - 14
= 16 - 14
= 2