Question
In a triangle, prove the perpendicular from the vertex opposite the side that is not less than either of the remaining sides falls within the triangle.
Answers
Steve
it is clearly true for all acute triangles.
In a right or obtuse triangle, the longest side is opposite the largest angle.
That vertex lies above the longest side, so the perpendicular meets the side within the triangle.
In a right or obtuse triangle, the longest side is opposite the largest angle.
That vertex lies above the longest side, so the perpendicular meets the side within the triangle.