Asked by Anonymous

Solve the quadratic inequality 2x^2 + x - 3 > 0

is this correct? I'm not sure what a solved quadratic inequality looks like.
2x^2 + x > 3
Answered by Reiny
2x^2 + x - 3 > 0
(2x + 3)(x - 1) > 0

which tells me that the x-intercepts of the parabola
y = 2x^2 + x - 3 are -3/2 and 1 and it opens upwards.

So for what values is the function above the x-axis ?
Answered by Damon
That is a parabola
for very large |x| , y is +
so it opens up (holds water)
so find the roots and any x< the lower one or > the upper one satisfies the condition
2 x^2 + x - 3 = 0
(2x-3)(x+1) = 0
any x < -1 is good
any x > 3/2 is good
in between , no good
Answered by Damon
woops sorry
(2x+3)(x-1) =0 for roots
x<-3/2 or x > 1
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