Asked by prudence
A 25,0ml sample of 0,105M HCl was tritrated with 31,5ml of NaOH.what is the concentration of the NaOH?
Answers
Answered by
DrBob222
millimols HCl = mL x M = ?
millimols NaOH used = mmols HCl since 1 mol HCl = 1 mol NaOH in the equation.
Then M NaOH = mmols/mL = ?
The equation is HCl + NaOH ==> NaCl + H2O
Post your work if you get stuck.
millimols NaOH used = mmols HCl since 1 mol HCl = 1 mol NaOH in the equation.
Then M NaOH = mmols/mL = ?
The equation is HCl + NaOH ==> NaCl + H2O
Post your work if you get stuck.
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