Question
A sample of a new plant food, "super gro", was analyzed. Determine the amount of grams of P and P2O5 as well as the percentage of P2O5 in a sample of "super gro".
Mass of plant food sample: 12.50 grams
Mass of MgNH4PO46H2O recovered: 8.93 grams
Mass of plant food sample: 12.50 grams
Mass of MgNH4PO46H2O recovered: 8.93 grams
Answers
DrBob222
mm = molar mass.
am = atomic mass.
grams P = grams MgNH4PO4.6H2O x (am P/mm MgNH4PO4.6H2O) = ?
Then % P = (grams P/mass sample)*100 =- ?
grams P2O5 = grams P x (mm P2O5/am P) = ?
Then % P2O5 =-(grams P2O5/mass sample)*100 = ?
Post your work if you get stuck.
am = atomic mass.
grams P = grams MgNH4PO4.6H2O x (am P/mm MgNH4PO4.6H2O) = ?
Then % P = (grams P/mass sample)*100 =- ?
grams P2O5 = grams P x (mm P2O5/am P) = ?
Then % P2O5 =-(grams P2O5/mass sample)*100 = ?
Post your work if you get stuck.