Z = (score-mean)/SD = (58-70)/15 = ?
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
A psychologist studied the time x (in seconds) it took a subject to complete a pencil and paper maze while in the presence of a floral scent. Suppose x has a normal distribution with mean 70 seconds and standard deviation 15 seconds. Find P(X<58)
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