Asked by Rachel
                Determine the expotential growth equation from the following table?
Year 2007: 1.6 million subscribers
Year 2008: 2.7
Year 2009: 4.4
Year 2010: 6.4
Year 2011: 8.9
Year 2012: 13.1
Year 2013: 19.3
Year 2014: 28.2
Year 2015: 38.2
Year 2016: 48.7
A. What is the expotential equation that you found?
B. Using the non rounded regression equation to determine during what year will the number of subscribers pass 100 000 000?
            
        Year 2007: 1.6 million subscribers
Year 2008: 2.7
Year 2009: 4.4
Year 2010: 6.4
Year 2011: 8.9
Year 2012: 13.1
Year 2013: 19.3
Year 2014: 28.2
Year 2015: 38.2
Year 2016: 48.7
A. What is the expotential equation that you found?
B. Using the non rounded regression equation to determine during what year will the number of subscribers pass 100 000 000?
Answers
                    Answered by
            Steve
            
    The ratio between terms is not quite constant, so I'll just take the 1st and last to figure out the average growth rate. The population grew from 1.6 to 48.7 million in 9 years, so
r = (48.7/1.6)^(1/9) = 1.4615
so, to find when the population reaches 100 million, we need
1.6 * 1.4615^t = 100
t = 10.8974
So, in 2007+10.89 or 2018 the population will reach 100 million
    
r = (48.7/1.6)^(1/9) = 1.4615
so, to find when the population reaches 100 million, we need
1.6 * 1.4615^t = 100
t = 10.8974
So, in 2007+10.89 or 2018 the population will reach 100 million
                    Answered by
            humungo dicco
            
    its not average growth rate lmao^
again stop deleting my legit comments.
yall want troll names answering legitly or idiots like this
    
again stop deleting my legit comments.
yall want troll names answering legitly or idiots like this
                    Answered by
            Steve
            
    If you want to use regression (which also, by the way, calculates a kind of average value), use linear regression on the log of the population.
    
                    Answered by
            Rachel 
            
    Thank you Steve :)
    
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