Asked by veronica
Sandy has $5,000 invested in three accounts. one account bears 2% annual interest, another 3% and other 5%. she has four times the amount invested at 5% as she does at 2%, and she earned $202.50 for the year. write and solve a system of equations to find out how much money Sandy has in each account.
2%=___________
3%=___________
5%=___________
2%=___________
3%=___________
5%=___________
Answers
Answered by
Reiny
I will get you going with the definition
amount invested at 2% ---- x
amount invested at 5% ---- 4x
amount invested at 3% ---- 5000 - 5x
return from the 2% account = .02x
return from the 5% account = .05(4x)
return from the 3% account = .....
Now their sum = 202.50
make up the equation, and solve
amount invested at 2% ---- x
amount invested at 5% ---- 4x
amount invested at 3% ---- 5000 - 5x
return from the 2% account = .02x
return from the 5% account = .05(4x)
return from the 3% account = .....
Now their sum = 202.50
make up the equation, and solve
Answered by
veronica
yes but i have to use the linear systems in three variables.
so like this .02x+.03y+.05z=5,000
so like this .02x+.03y+.05z=5,000
Answered by
Henry
Invested $X at 2%.
Invested $4x at 5%.
Invested $(5000 - 5x) at 3%.
I = Po1*r1*t + Po2*r2*t + Po3*r3*t = 202.50.
x*0.02*1 + 4x*0.05*1 + (5000-5x)*0.03*1 = 202.50,
X = ?
4x = ?
5000-5x = ?
Invested $4x at 5%.
Invested $(5000 - 5x) at 3%.
I = Po1*r1*t + Po2*r2*t + Po3*r3*t = 202.50.
x*0.02*1 + 4x*0.05*1 + (5000-5x)*0.03*1 = 202.50,
X = ?
4x = ?
5000-5x = ?
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