Assuming the given expression is n(t) = n(0) * e^(0.15t),
Given:
In the year 1995, t = 0
n(0) = 20
a) t = 10
n(t) = n(0) * e^(0.15t)
= 20 * e^(0.15*10)
= 20 * e^(1.5)
b)
n(t) = 400
n(t) = n(0) * e^(0.15t)
= 20 * e^(0.15*t)
400 = 20 * e^(0.15*t)
Solve for t.
The growth of stray cat population, n(t) in a small town can be modeled as n(t) = no e 0.15 t where t is time in years.
Given that in year 1995, the town had 20 stray cats.
a) Find the projected population after 10 years
b) Find the number of years required for the stray-cat population to reach 400.
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