Asked by Andrea
                Multiply and Simplify.(∛x +2)(∛(x^2)-2∛x +4) Pleaseeeeee helpppppp!!!!!!! :(
            
            
        Answers
                    Answered by
            Arora
            
    Use the distributive property:
(∛x +2)(∛(x^2)-2∛x +4)
= (∛x)(∛(x^2)) + 2(∛(x^2)) + (∛x)(-2∛x) + 2(-2∛x) + 4(∛x) + 4*2
(When the same base with different exponents is multiplied, the exponents are added, also,
∛x = x^(1/3), ∛(x^2) = x^(2/3))
= (∛x)(∛(x^2)) + 2(∛(x^2)) + (∛x)(-2∛x) + 2(-2∛x) + 4(∛x) + 4*2
= x + 2*x^(2/3) - 2*x^(2/3) - 4*x^(1/3) + 4*x^(1/3) + 8
= x + 8
    
(∛x +2)(∛(x^2)-2∛x +4)
= (∛x)(∛(x^2)) + 2(∛(x^2)) + (∛x)(-2∛x) + 2(-2∛x) + 4(∛x) + 4*2
(When the same base with different exponents is multiplied, the exponents are added, also,
∛x = x^(1/3), ∛(x^2) = x^(2/3))
= (∛x)(∛(x^2)) + 2(∛(x^2)) + (∛x)(-2∛x) + 2(-2∛x) + 4(∛x) + 4*2
= x + 2*x^(2/3) - 2*x^(2/3) - 4*x^(1/3) + 4*x^(1/3) + 8
= x + 8
                    Answered by
            Steve
            
    recall that a^3+b^3 = (a+b)(a^2-ab+b^2)
here you have a=∛x and b=2
(∛x +2)(∛(x^2)-2∛x +4) =(∛x)^3+2^3 = x+8
    
here you have a=∛x and b=2
(∛x +2)(∛(x^2)-2∛x +4) =(∛x)^3+2^3 = x+8
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