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If salicylic acid costs $21 per kilogram, how much would it cost to purchase enough salicylic acid (formula mass= 138.1) to mak...Asked by Jorge
If salicylic acid costs $21 per kilogram, how much would it cost to purchase enough salicylic acid (formula mass= 138.1) to make 1.0 kilogram of aspirin (formula mass= 180.2), assuming your percent yield was obtained in the reaction? (Note 1 to 1 mole ration in equation).
Hint: This is a two step process. First use the % yield relationship to calculate theoretical amount of aspirin needed to get an actual amount of 1.0 Kg of aspirin. Then use the stoichiometric relation from the chemical equation to calculate how much salicylic acid would be needed to make that much aspirin.
I don't know how to setup!
Hint: This is a two step process. First use the % yield relationship to calculate theoretical amount of aspirin needed to get an actual amount of 1.0 Kg of aspirin. Then use the stoichiometric relation from the chemical equation to calculate how much salicylic acid would be needed to make that much aspirin.
I don't know how to setup!
Answers
Answered by
DrBob222
Bob Pursley told you yesterday in your post of this same question that the hint told it all. So you do the two step tango. Have you used % yield to calculate the theoretical amount of aspirin need to get 1.0 kg?
% yield = [(actual amount/theoretical amount)]*100 = ?
Second step is to use stoichiometry to calculate the amount salicylic acid you need.
% yield = [(actual amount/theoretical amount)]*100 = ?
Second step is to use stoichiometry to calculate the amount salicylic acid you need.
Answered by
Jorge
Still have no clue what goes where!
Answered by
DrBob222
C'mon. I assume you have done an experiment that determined the % yield for the reaction. That goes in for % yield in my last response to you. Plug that in. You want 1 kg. That goes in for the amount you want. Solve for the theoretical amount you must start with.
I assume you know how to do stoichiometry for the second part.
I assume you know how to do stoichiometry for the second part.
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